10/4/2023 0 Comments Whats a line of reflection![]() The figure on the right is the mirror image of the. I walked through the equations a few hundred times, and was able to figure out what is happening physically. Reflection is flipping an object across a line without changing its size or shape. A reflection is a transformation that maps a gure to its re ection image. The line m is called the reflecting line or line of reflection. the point A such that m is the perpendicular bisector of AA, if A is not on m. Is this some application of Len's Law? Or is there something that I am missing? Also, what happens when the reflected wave reaches the voltage source? There would be an enforcement of some voltage so would it be inverted again?įor the open circuit case, I understand that voltage "Piles up" at the end of the transmission line since there is no path for it to continue traveling, but why is it twice as much voltage as what is started with? Mathematically, it makes sense, but I still don't understand this physically.Īny help would be great, I am very confused about this topic and would like to get a firm physical understanding before accepting the equations. Recall from geometry that the reflection image of a point A over a line m is: 1. A voltage wave (stepping from VS/2 down to 0V) propogates in the reverse direction, and the current behind this wave is double the original current ahead of it.īut I don't understand why additional current flows into the short. Therefore, additional current flows into the short, and this current is equal to VS/2 divided by Z0 (which happens to be equal to the original current flowing into the line). I would like a non-mathematical explanation seems to answer the question withīut now we have another unstable situation: That end of the line is at 0V, but the rest of the line is still charged to Vs/2. In this post On a transmission line why are voltage and current waves reflected at a short circuit? the answer makes sense in a power perspective for the short circuit case, but I don't understand why the reflected wave is inverted. However, I don't understand what is happening in the closed and open circuit cases. ![]() which is the basic process of XRF, or what is called an Auger electron. Which means that there is no reflection, and physically it makes sense because the resistor is dissipating power through it, and so therefore the wave cannot propagate back. Normally, X-ray spectra consist of two different parts, the line spectrum and. I understand that when when a transmission line is terminated with a resistance equal to the transmission line impedance, then I am having trouble understanding what is happening physically during a transmission line reflection, in particular the short circuit and open circuit case.
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